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Worked example Calculating the amount of product formed from a limiting reactant
Problems Limiting Excess Reagents For the reaction 2S s 302 g 2S03 g if 6 3 g of S is reacted with 10 0 g of 02 show by calculation which one will be the limiting reactant For the reaction CaC03 s 2HCl aq CaC12 aq CO2 g H20 l 68 1 g solid CaC03 is mixed with 51 6 g HCl What number of grams of
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Detailed Solutions to Limiting Reagent Problems 1 Disulfur dichloride is prepared by direct reaction of the elements S s 4 Cl 8 2 g 4 S Cl 2 2 l What is the maximum amount of S Cl that could be made by the reaction of 64 0 g 2 2 of sulfur with 142 g of chlorine
Limiting Reactants worksheets questions and revision for GCSE Combined Science and Chemistry All the revision you need in one place
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Limiting Reactant and Percent Yield Practice Name 1 Consider the following reaction NH4NO3 Na3PO4 NH4 3PO4 NaNO3 Which reactant is limiting assuming we started with 30 0 grams of ammonium nitrate and 50 0 grams of
In each example one of the reactants is in excess Work out how many moles of the products are formed in each case 1 CaO H2O Ca OH 2 2 mol
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Problems Limiting Excess Reagents For the reaction 2S s 302 g 2S03 g if 6 3 g of S is reacted with 10 0 g of 02 show by calculation which one will be the limiting reactant For the reaction CaC03 s 2HCl aq CaC12 aq CO2 g H20 l 68 1 g solid CaC03 is mixed with 51 6 g HCl What number of grams of
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To determine the amounts of product either grams or moles you must start with the limiting reagent Use the amount that you have not the amount you need To determine the grams of excess reagent subtract the amount you need from the amount that you have then using the molar mass convert the moles left to grams
Problems Limiting Excess Reagents For the reaction 2S s 302 g 2S03 g if 6 3 g of S is reacted with 10 0 g of 02 show by calculation which one will be the limiting reactant For the reaction CaC03 s 2HCl aq CaC12 aq CO2 g H20 l 68 1 g solid CaC03 is mixed with 51 6 g HCl What number of grams of
To determine the amounts of product either grams or moles you must start with the limiting reagent Use the amount that you have not the amount you need To determine the grams of excess reagent subtract the amount you need from the amount that you have then using the molar mass convert the moles left to grams
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