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Molarity Practice Problems Answer Key
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Calculate the molarity of each of the following solutions a 0 195 g of cholesterol C 27 H 46 O in 0 100 L of serum the average concentration of cholesterol in human serum b 4 25 g of NH 3 in 0 500 L of solution the concentration of NH 3 in household ammonia
Molarity Calculations Calculate the molarities of the following solutions 2 3 moles of sodium chloride in 0 45 liters of solution 1 2 moles of calcium carbonate in 1 22 liters of solution 0 09 moles of sodium sulfate in 12 ml of solution
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Molarity Practice Worksheet
Molarity Practice Worksheet
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Problem 1 Sea water contains roughly 28 0 g of NaCl per liter What is the molarity of sodium chloride in sea water Solution MV grams molar mass x 1 00 L 28 0 g 58 443 g mol 1 x 0 4790993 M to three significant figures 0 479 M Problem 2 What is the molarity of 245 0 g of H 2 SO 4 dissolved in 1 000 L of solution Solution
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Molarity Practice Worksheet Answer Ivuyteq
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Molarity Practice Problems Answer Key 1 How many grams of potassium carbonate are needed to make 200 mL of a 2 5 M solution 69 1 grams 2 How many liters of water are needed to make a 4 M solution using 100 grams of lithium bromide 3 47 L
Molarity Practice Problems assume all solutions are aqueous 1 How many grams of potassium carbonate are needed to make 200 0 mL of a 2 5 M solution 2 How many liters of 4 0 M solution can be made using 100 0 grams of lithium bromide 3 What is the concentration of 450 0 mL of solution that contains 200 0 grams of iron II chloride 4
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Molarity Calculations Calculate the molarities of the following solutions 2 3 moles of sodium chloride in 0 45 liters of solution 1 2 moles of calcium carbonate in 1 22 liters of solution 0 09 moles of sodium sulfate in 12 ml of solution
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Molarity Practice Problems 1 Answer Key 1 How many grams of potassium carbonate are needed to make 280 mL of a 2 5 M solution Using the molarity equation M mol L we can find that we ll need 0 70 mol of potassium carbonate Given that the molar mass of K2CO3 is 138 21 g mol this means that we ll require 97 grams
Molarity Calculations Calculate the molarities of the following solutions 2 3 moles of sodium chloride in 0 45 liters of solution 1 2 moles of calcium carbonate in 1 22 liters of solution 0 09 moles of sodium sulfate in 12 ml of solution
Molarity Practice Problems 1 Answer Key 1 How many grams of potassium carbonate are needed to make 280 mL of a 2 5 M solution Using the molarity equation M mol L we can find that we ll need 0 70 mol of potassium carbonate Given that the molar mass of K2CO3 is 138 21 g mol this means that we ll require 97 grams
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