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How Many Sides Does A Polygon Have If The Sum Of Interior Angles Is 1260
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To calculate the sum of interior angles start by counting the number of sides in your polygon Next plug this number into the formula for the n value Then solve for n by subtracting 2 from the number of sides and multiplying the difference by
The General Rule Each time we add a side triangle to quadrilateral quadrilateral to pentagon etc we add another 180 to the total So the general rule is Sum of Interior Angles n 2 180 Each Angle of a Regular Polygon n 2 180 n Perhaps an example will help Example What about a Regular Decagon 10 sides
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Interior Angles Of Regular Polygons A Plus Topper
Interior Angles Of Regular Polygons A Plus Topper
We will learn how to find the sum of the interior angles of a polygon having n sides We know that if a polygon has n sides then it is divided into n 2 triangles We also know that the sum of the angles of a triangle 180
To calculate the sum of interior angles of a polygon you need its number of sides Mathematically the sum of the angles is expressed as Sum of interior angles of a polygon n 2 times 180 circ Where n is the number of sides of the polygon The angle is measured in degrees
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Interior Angles Of Polygons Mr Mathematics
Interior Angles Of Polygons Mr Mathematics
So the sum of the interior angles of a polygon can be found by taking the number of sides subtracting 2 and then multiplying by 180 The sum of the interior angles of an octagon is 1080
In any polygon the sum of an interior angle and its corresponding exterior angle is 180 Note If a polygon has n number of sides then it would have n number of vertices n number of interior angles and n number of exterior angles
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The General Rule Each time we add a side triangle to quadrilateral quadrilateral to pentagon etc we add another 180 to the total So the general rule is Sum of Interior Angles n 2 180 Each Angle of a Regular Polygon n 2 180 n Perhaps an example will help Example What about a Regular Decagon 10 sides
https://byjus.com/question-answer/find-the-number...
Find the number of sides in a polygon if the sum of its interior angles is i 900o ii 1620o iii 16 right angles iv right angles Solution i Let no of sides n Sum of angles of polygon 900o n 2 180o 900o n 2 900 180 n 2 5 n 5 2 n 7 ii Let no of sides n Sum of angles of polygon 1620o
The General Rule Each time we add a side triangle to quadrilateral quadrilateral to pentagon etc we add another 180 to the total So the general rule is Sum of Interior Angles n 2 180 Each Angle of a Regular Polygon n 2 180 n Perhaps an example will help Example What about a Regular Decagon 10 sides
Find the number of sides in a polygon if the sum of its interior angles is i 900o ii 1620o iii 16 right angles iv right angles Solution i Let no of sides n Sum of angles of polygon 900o n 2 180o 900o n 2 900 180 n 2 5 n 5 2 n 7 ii Let no of sides n Sum of angles of polygon 1620o
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